What is (-2^2-4(-2)+4)/6 ?

The solution to (-2^2-4(-2)+4)/6 is 1 1/3

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Popular >

(-2^2-4(-2)+4)/6

Solution

\frac{- 2 ^{2} - 4 ( - 2 ) + 4}{6}

Solution

1 \frac{1}{3}

Solution steps

\frac{- 2 ^{2} - 4 ( - 2 ) + 4}{6}

Solve

- 2^{2} - 4 (- 2) + 4 : 8

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= - 4 - 4 (- 2) + 4

Multiply and divide (left to right)

4 (- 2) : - 8

4 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 2) = - 4 \cdot 2 = - 8

= - 8

= - 4 - (- 8) + 4

Add and subtract (left to right)

- 4 - (- 8) + 4 : 8

- 4 - (- 8) + 4

Apply rule

- (- a) = + a

- (- 8) = + 8

= - 4 + 8 + 4

- 4 + 8 = 4

= 4 + 4

4 + 4 = 8

= 8

= 8

= \frac{8}{6}

Simplify

\frac{8}{6} : 1 \frac{1}{3}

Cancel the common factor:

2

= \frac{4}{3}

Convert improper fractions to mixed numbers:

\frac{4}{3} = 1 \frac{1}{3}

\frac{4}{3} = 1

Remainder

1

\frac{4}{3}

Write the problem in long division format

3 \overline{∣ 4}

Divide

4

3

to get

1

Divide

4

3

to get

1

1 3 \overline{∣ 4}

Multiply the quotient digit

(1)

by the divisor

3

1 3 \overline{∣ 4} \underline{3}

Subtract

3

from

4

1 3 \overline{∣ 4} \underline{3} 1

1 3 \overline{∣ 4} \underline{3} 1

The solution for Long Division of

\frac{4}{3}

1

with remainder of

1

1 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{4}{3} = 1 \frac{1}{3}

= 1 \frac{1}{3}

= 1 \frac{1}{3}

= 1 \frac{1}{3}

Popular Examples

(9(4)-2(-2))/((4)(-2))

\frac{9 ( 4 ) - 2 ( - 2 )}{( 4 ) ( - 2 )}

[(-3)\div (-4)]\div [(-15)\div (+8)]

[(- 3) \div (- 4)] \div [(- 15) \div (+ 8)]

4+2\div 2

4 + 2 \div 2

-8\times (-6)+4\times (-6)

- 8 \times (- 6) + 4 \times (- 6)

(45/1^5)/(9/1^4)

\frac{45/ 1 ^{5}}{9/ 1 ^{4}}

Frequently Asked Questions (FAQ)

What is (-2^2-4(-2)+4)/6 ?
The solution to (-2^2-4(-2)+4)/6 is 1 1/3