What is -3(-6+4)^2+3 ?

The solution to -3(-6+4)^2+3 is -9

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-3(-6+4)^2+3

- 3 (- 6 + 4)^{2} + 3

- 9

Solution steps

- 3 (- 6 + 4)^{2} + 3

Follow the PEMDAS order of operations

Calculate within parentheses

(- 6 + 4) : - 2

- 6 + 4

- 6 + 4 = - 2

= - 2

= - 3 (- 2)^{2} + 3

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 3 \cdot 4 + 3

Multiply and divide (left to right)

- 3 \cdot 4 : - 12

- 3 \cdot 4

- 3 \cdot 4 = - 12

= - 12

= - 12 + 3

Add and subtract (left to right)

- 12 + 3 : - 9

- 12 + 3

- 12 + 3 = - 9

= - 9

= - 9

4 - 5 (- 4 - 2)

3 \times (- 3) + 2

3^{2} + (- 2^{2})

\frac{10}{10 \times \frac{1}{2} + 1}

\frac{2}{7} - (\frac{1}{7} - \frac{8}{3})