What is (5/3-4)\times 2-2/3 ?

The solution to (5/3-4)\times 2-2/3 is -16/3

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(5/3-4)\times 2-2/3

(\frac{5}{3} - 4) \cdot 2 - \frac{2}{3}

- \frac{16}{3}

Solution steps

(\frac{5}{3} - 4) \cdot 2 - \frac{2}{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{5}{3} - 4) : - \frac{7}{3}

\frac{5}{3} - 4

\frac{5}{3} - 4 = - \frac{7}{3}

\frac{5}{3} - 4

Convert element to fraction:

4 = \frac{4 \cdot 3}{3}

= - \frac{4 \cdot 3}{3} + \frac{5}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 4 \cdot 3 + 5}{3}

- 4 \cdot 3 + 5 = - 7

- 4 \cdot 3 + 5

Multiply the numbers:

4 \cdot 3 = 12

= - 12 + 5

Add/Subtract the numbers:

- 12 + 5 = - 7

= - 7

= \frac{- 7}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{7}{3}

= - \frac{7}{3}

= - \frac{7}{3} \cdot 2 - \frac{2}{3}

Multiply and divide (left to right)

- \frac{7}{3} \cdot 2 : - \frac{14}{3}

- \frac{7}{3} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{7}{3} \cdot \frac{2}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{7}{3} \cdot \frac{2}{1} = \frac{7 \cdot 2}{3 \cdot 1}

= - \frac{7 \cdot 2}{3 \cdot 1}

Multiply the numbers:

7 \cdot 2 = 14

= - \frac{14}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= - \frac{14}{3}

= - \frac{14}{3} - \frac{2}{3}

Add and subtract (left to right)

- \frac{14}{3} - \frac{2}{3} : - \frac{16}{3}

- \frac{14}{3} - \frac{2}{3}

- \frac{14}{3} - \frac{2}{3} = - \frac{16}{3}

- \frac{14}{3} - \frac{2}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 14 - 2}{3}

Subtract the numbers:

- 14 - 2 = - 16

= \frac{- 16}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{16}{3}

= - \frac{16}{3}

= - \frac{16}{3}

- (0)^{2} + 4 (0)

3 (4)^{2} - 6 (4) - 8

3 (4)^{2} - 6 (4) - 9

3 \cdot 10 + 8 - 4^{2}

\frac{3}{8} + \frac{5}{8}