What is [4\div 7(6+40)-5\div 4(7-9+54)]\times 5 ?

The solution to [4\div 7(6+40)-5\div 4(7-9+54)]\times 5 is -1355/7

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Popular >

[4\div 7(6+40)-5\div 4(7-9+54)]\times 5

Solution

[4 \div 7 (6 + 40) - 5 \div 4 (7 - 9 + 54)] \times 5

Solution

- \frac{1355}{7}

Solution steps

[4 \div 7 (6 + 40) - 5 \div 4 (7 - 9 + 54)] \times 5

Follow the PEMDAS order of operations

Calculate within parentheses

[4 \div 7 (6 + 40) - 5 \div 4 (7 - 9 + 54)] : - \frac{271}{7}

4 \div 7 (6 + 40) - 5 \div 4 (7 - 9 + 54)

Calculate within parentheses

(6 + 40) : 46

6 + 40

6 + 40 = 46

= 46

= 4 \div 7 \cdot 46 - 5 \div 4 (7 - 9 + 54)

Calculate within parentheses

(7 - 9 + 54) : 52

7 - 9 + 54

Add and subtract (left to right)

7 - 9 = - 2

= - 2 + 54

- 2 + 54 = 52

= 52

= 4 \div 7 \cdot 46 - 5 \div 4 \cdot 52

Multiply and divide (left to right)

4 \div 7 \cdot 46 : \frac{184}{7}

4 \div 7 \cdot 46

4 \div 7 = \frac{4}{7}

= \frac{4}{7} \cdot 46

\frac{4}{7} 46 = \frac{184}{7}

\frac{4}{7} \cdot 46

Convert element to fraction:

46 = \frac{46}{1}

= \frac{4}{7} \cdot \frac{46}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 46}{7 \cdot 1}

Multiply the numbers:

4 \cdot 46 = 184

= \frac{184}{7 \cdot 1}

Multiply the numbers:

7 \cdot 1 = 7

= \frac{184}{7}

= \frac{184}{7}

= \frac{184}{7} - 5 \div 4 \cdot 52

Multiply and divide (left to right)

5 \div 4 \cdot 52 : 65

5 \div 4 \cdot 52

5 \div 4 = \frac{5}{4}

= \frac{5}{4} \cdot 52

\frac{5}{4} 52 = 65

\frac{5}{4} \cdot 52

Convert element to fraction:

52 = \frac{52}{1}

= \frac{5}{4} \cdot \frac{52}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 \cdot 52}{4 \cdot 1}

Cancel

\frac{5 \cdot 52}{4 \cdot 1} : 65

\frac{5 \cdot 52}{4 \cdot 1}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{5 \cdot 52}{4}

Divide the numbers:

\frac{52}{4} = 13

= 5 \cdot 13

Multiply the numbers:

5 \cdot 13 = 65

= 65

= 65

= 65

= \frac{184}{7} - 65

Add and subtract (left to right)

\frac{184}{7} - 65 : - \frac{271}{7}

\frac{184}{7} - 65

\frac{184}{7} - 65 = - \frac{271}{7}

\frac{184}{7} - 65

Convert element to fraction:

65 = \frac{65 \cdot 7}{7}

= - \frac{65 \cdot 7}{7} + \frac{184}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 65 \cdot 7 + 184}{7}

- 65 \cdot 7 + 184 = - 271

- 65 \cdot 7 + 184

Multiply the numbers:

65 \cdot 7 = 455

= - 455 + 184

Add/Subtract the numbers:

- 455 + 184 = - 271

= - 271

= \frac{- 271}{7}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{271}{7}

= - \frac{271}{7}

= - \frac{271}{7}

= - \frac{271}{7} \times 5

Multiply and divide (left to right)

- \frac{271}{7} \times 5 : - \frac{1355}{7}

- \frac{271}{7} \times 5

Convert element to fraction:

5 = \frac{5}{1}

= - \frac{271}{7} \cdot \frac{5}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{271}{7} \cdot \frac{5}{1} = \frac{271 \cdot 5}{7 \cdot 1}

= - \frac{271 \cdot 5}{7 \cdot 1}

Multiply the numbers:

271 \cdot 5 = 1355

= - \frac{1355}{7 \cdot 1}

Multiply the numbers:

7 \cdot 1 = 7

= - \frac{1355}{7}

= - \frac{1355}{7}

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Frequently Asked Questions (FAQ)

What is [4\div 7(6+40)-5\div 4(7-9+54)]\times 5 ?
The solution to [4\div 7(6+40)-5\div 4(7-9+54)]\times 5 is -1355/7