What is 6/((1+1)^4) ?

The solution to 6/((1+1)^4) is 3/8

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6/((1+1)^4)

\frac{6}{( 1 + 1 ) ^{4}}

\frac{3}{8}

Solution steps

\frac{6}{( 1 + 1 ) ^{4}}

Solve

(1 + 1)^{4} : 16

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + 1) : 2

1 + 1

1 + 1 = 2

= 2

= 2^{4}

Calculate exponents

2^{4} : 16

2^{4}

2^{4} = 16

= 16

= 16

= \frac{6}{16}

Cancel the common factor:

2

= \frac{3}{8}

- 101 + 33 + 108 - 100

\frac{80 0 ^{4}}{4 ( 2 ) ( 8 ) ^{3}}

3 \times + 2 - 4

(4 - 1 \cdot (3 - 1)) - 3

64 - (7 \times 8) \div 4