What is (4\times 2^2-0+4\times 1^2)/(2-0) ?

The solution to (4\times 2^2-0+4\times 1^2)/(2-0) is 10

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(4\times 2^2-0+4\times 1^2)/(2-0)

\frac{4 \cdot 2 ^{2} - 0 + 4 \cdot 1 ^{2}}{2 - 0}

10

Solution steps

\frac{4 \cdot 2 ^{2} - 0 + 4 \cdot 1 ^{2}}{2 - 0}

Solve

4 \cdot 2^{2} - 0 + 4 \cdot 1^{2} : 20

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 \cdot 4 - 0 + 4 \cdot 1^{2}

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= 4 \cdot 4 - 0 + 4 \cdot 1

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 16 - 0 + 4 \cdot 1

Multiply and divide (left to right)

4 \cdot 1 : 4

4 \cdot 1

4 \cdot 1 = 4

= 4

= 16 - 0 + 4

Add and subtract (left to right)

16 - 0 + 4 : 20

16 - 0 + 4

16 - 0 = 16

= 16 + 4

16 + 4 = 20

= 20

= 20

Solve

2 - 0 : 2

2 - 0 = 2

= 2

= \frac{20}{2}

Divide the numbers:

\frac{20}{2} = 10

= 10

54 - (12 + 38)

5 \div 7 - 1

8 - 7 \times [4 - (4^{3} + 7)]

5^{0} \times 5^{2} + 5^{2} \div 5^{2}

2 \times 4 - 15 \div 3

What is (4\times 2^2-0+4\times 1^2)/(2-0) ?
The solution to (4\times 2^2-0+4\times 1^2)/(2-0) is 10