What is (1/2*(-4))^2 ?

The solution to (1/2*(-4))^2 is 4

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(1/2*(-4))^2

(\frac{1}{2} \cdot (- 4))^{2}

4

Solution steps

(\frac{1}{2} (- 4))^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{1}{2} \cdot (- 4)) : - 2

\frac{1}{2} (- 4)

Multiply and divide (left to right)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{2} (- 4) = - \frac{1}{2} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= - \frac{1}{2} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{1}{2} \cdot \frac{4}{1} = \frac{1 \cdot 4}{2 \cdot 1}

= - \frac{1 \cdot 4}{2 \cdot 1}

\frac{1 \cdot 4}{2 \cdot 1} = 2

\frac{1 \cdot 4}{2 \cdot 1}

\frac{1 \cdot 4}{2 \cdot 1} = \frac{4}{2}

\frac{1 \cdot 4}{2 \cdot 1}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{4}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{4}{2}

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= - 2

= (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4

(2^{6} \div 2^{4}) + 2^{2}

3^{8} - 2^{8}

1 \frac{1}{3} \div 3 - \frac{5}{18}

9 - \frac{2}{3} - \frac{1}{2}

2^{4} + (2^{5} \times (2^{3} - 2^{2}))