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受欢迎的初等代数 >

(4-1/4)× (5-1/5)

解答

(4 - \frac{1}{4}) \cdot (5 - \frac{1}{5})

解答

18

求解步骤

(4 - \frac{1}{4}) (5 - \frac{1}{5})

遵循 PEMDAS 运算顺序

计算括号内的值

(4 - \frac{1}{4}) : \frac{15}{4}

4 - \frac{1}{4}

4 - \frac{1}{4} = \frac{15}{4}

4 - \frac{1}{4}

将项转换为分式:

4 = \frac{4 \cdot 4}{4}

= \frac{4 \cdot 4}{4} - \frac{1}{4}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 4 - 1}{4}

4 \cdot 4 - 1 = 15

4 \cdot 4 - 1

数字相乘:

4 \cdot 4 = 16

= 16 - 1

数字相减:

16 - 1 = 15

= 15

= \frac{15}{4}

= \frac{15}{4}

= \frac{15}{4} (5 - \frac{1}{5})

计算括号内的值

(5 - \frac{1}{5}) : \frac{24}{5}

5 - \frac{1}{5}

5 - \frac{1}{5} = \frac{24}{5}

5 - \frac{1}{5}

将项转换为分式:

5 = \frac{5 \cdot 5}{5}

= \frac{5 \cdot 5}{5} - \frac{1}{5}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 \cdot 5 - 1}{5}

5 \cdot 5 - 1 = 24

5 \cdot 5 - 1

数字相乘:

5 \cdot 5 = 25

= 25 - 1

数字相减:

25 - 1 = 24

= 24

= \frac{24}{5}

= \frac{24}{5}

= \frac{15}{4} \cdot \frac{24}{5}

乘除（左右）

\frac{15}{4} \cdot \frac{24}{5} : 18

\frac{15}{4} \cdot \frac{24}{5}

使用分式法则:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{15 \cdot 24}{4 \cdot 5}

消掉

\frac{15 \cdot 24}{4 \cdot 5} : 18

\frac{15 \cdot 24}{4 \cdot 5}

因式分解数字:

15 = 5 \cdot 3

= \frac{5 \cdot 3 \cdot 24}{4 \cdot 5}

约分:

5

= \frac{3 \cdot 24}{4}

数字相除:

\frac{24}{4} = 6

= 3 \cdot 6

数字相乘:

3 \cdot 6 = 18

= 18

= 18

= 18

流行的例子

1 0^{2} + 2 5^{2}

(3-2+1)× (1+1-1)

(3 - 2 + 1) \times (1 + 1 - 1)

1 - 2 - 9 - 20 - 108 + 4

- 2 + 5 - (- 1)

3^{3} - 8 + 0