What is 3\times (2+4^3)\div 4 ?

The solution to 3\times (2+4^3)\div 4 is 49 1/2

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3\times (2+4^3)\div 4

3 \times (2 + 4^{3}) \div 4

49 \frac{1}{2}

Solution steps

3 \times (2 + 4^{3}) \div 4

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 4^{3}) : 66

= 3 \times 66 \div 4

Multiply and divide (left to right)

3 \times 66 \div 4 : \frac{198}{4}

= \frac{198}{4}

Simplify

\frac{198}{4} : 49 \frac{1}{2}

Cancel the common factor:

2

= \frac{99}{2}

Convert improper fractions to mixed numbers:

\frac{99}{2} = 49 \frac{1}{2}

= 49 \frac{1}{2}

- 125 + (- 35) + 140

(- 2)^{3} - (- 1)^{2} + (- 3^{2}) - (- 2)^{5}

5 (2) - 4 (9)

3 - 2 \times [5 - (5^{3} + 2)]

(- 2 + 9) \times (- 6 - 4) \div (6 - 1)