What is (6+3/4)-(3+2/3) ?

The solution to (6+3/4)-(3+2/3) is 3 1/12

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(6+3/4)-(3+2/3)

(6 + \frac{3}{4}) - (3 + \frac{2}{3})

3 \frac{1}{12}

Solution steps

(6 + \frac{3}{4}) - (3 + \frac{2}{3})

Follow the PEMDAS order of operations

Calculate within parentheses

(6 + \frac{3}{4}) : \frac{27}{4}

= \frac{27}{4} - (3 + \frac{2}{3})

Calculate within parentheses

(3 + \frac{2}{3}) : \frac{11}{3}

= \frac{27}{4} - \frac{11}{3}

Add and subtract (left to right)

\frac{27}{4} - \frac{11}{3} : \frac{37}{12}

= \frac{37}{12}

Convert improper fractions to mixed numbers:

\frac{37}{12} = 3 \frac{1}{12}

= 3 \frac{1}{12}

(6 - \frac{5}{2}) (3 + \frac{8}{3})

(3)^{2} - (12 - 6) + 7 + 5 (6 + 2)^{2}

11 + [(5 - 4) \times (3 - 2 - 1)]

15 (2)^{2} + 10 (2)

\frac{1}{2} + 15 \div 3 + (4^{2} + 3)