What is (5^3+8^2)/(3^4-16^2-8^2) ?

The solution to (5^3+8^2)/(3^4-16^2-8^2) is -189/239

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5^3+8^2)/(3^4-16^2-8^2)

\frac{5 ^{3} + 8 ^{2}}{3 ^{4} - 1 6 ^{2} - 8 ^{2}}

- \frac{189}{239}

Solution steps

\frac{5 ^{3} + 8 ^{2}}{3 ^{4} - 1 6 ^{2} - 8 ^{2}}

Solve

5^{3} + 8^{2} : 189

Follow the PEMDAS order of operations

Calculate exponents

5^{3} : 125

5^{3}

5^{3} = 125

= 125

= 125 + 8^{2}

Calculate exponents

8^{2} : 64

8^{2}

8^{2} = 64

= 64

= 125 + 64

Add and subtract (left to right)

125 + 64 : 189

125 + 64

125 + 64 = 189

= 189

= 189

Solve

3^{4} - 1 6^{2} - 8^{2} : - 239

Follow the PEMDAS order of operations

Calculate exponents

3^{4} : 81

3^{4}

3^{4} = 81

= 81

= 81 - 1 6^{2} - 8^{2}

Calculate exponents

1 6^{2} : 256

1 6^{2}

1 6^{2} = 256

= 256

= 81 - 256 - 8^{2}

Calculate exponents

8^{2} : 64

8^{2}

8^{2} = 64

= 64

= 81 - 256 - 64

Add and subtract (left to right)

81 - 256 - 64 : - 239

81 - 256 - 64

81 - 256 = - 175

= - 175 - 64

- 175 - 64 = - 239

= - 239

= - 239

= \frac{189}{- 239}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{189}{239}

7 + 3 \cdot 4 - 2

- 2 (- 1) + \frac{1}{4}

12 \times (3 + 2)^{2} \div 2 - 10

- 2 (- 3)^{2} - 8 (- 3) - 4

5^{0} + 5^{1}

What is (5^3+8^2)/(3^4-16^2-8^2) ?
The solution to (5^3+8^2)/(3^4-16^2-8^2) is -189/239