What is primefactorization 2925 ?

The solution to primefactorization 2925 is 3^2*5^2*13

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Find the Prime Factorization 2925

prime factorization

2925

3^{2} \cdot 5^{2} \cdot 13

Solution steps

2925

2925

divides by

32925 = 975 \cdot 3

= 3 \cdot 975

975

divides by

3975 = 325 \cdot 3

= 3 \cdot 3 \cdot 325

325

divides by

5325 = 65 \cdot 5

= 3 \cdot 3 \cdot 5 \cdot 65

65

divides by

565 = 13 \cdot 5

= 3 \cdot 3 \cdot 5 \cdot 5 \cdot 13

3, 5, 13

are all prime numbers, therefore no further factorization is possible

= 3 \cdot 3 \cdot 5 \cdot 5 \cdot 13

= 3^{2} \cdot 5^{2} \cdot 13

ro u n d t o t h e n e a res t t e n t h 43.96

180 - 73

50 - 26

14 \cdot 12

\frac{58}{9}

What is primefactorization 2925 ?
The solution to primefactorization 2925 is 3^2*5^2*13