What is longmult 22*15 ?

The solution to longmult 22*15 is 330

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Multiply 22*15

long multiplication

22 \cdot 15

330

Solution steps

22 \cdot 15

Line up the numbers

\times 2125

Multiply the top number by the bottom number one digit at a time starting with the ones digit (from right to left)

Multiply the top number by the bolded digit of the bottom number

\times 2125

Mutliply the bold numbers:

2 \cdot 5 = 10

Carry

1

to the column on the left and write

0

in the result line

\frac{\times 1 2 1 2 5}{0}

Add the carried number to the multiplication:

1 + 2 \cdot 5 = 11

Carry

1

to the column on the left and write

1

in the result line

\frac{\times 1 1 2 1 2 5}{1 0}

Add the carried digit,

1

, to the result

\frac{\times 1 1 2 1 2 5}{1 1 0}

Multiply the top number by the bolded digit of the bottom number

\frac{\times 2 1 2 5}{1 1 0}

Mutliply the bold numbers:

2 \cdot 1 = 2

\frac{\times 2 1 2 5}{1 1 2 0}

Mutliply the bold numbers:

2 \cdot 1 = 2

\frac{\times 2 1 2 5}{1 2 1 2 0}

Add the rows to get the answer. For simplicity, fill in trailing zeros

\frac{\times 2 1 2 5}{1 2 1 2 0 0}

110 + 220 = 330

+ 121200

Add the digits of the bolded column:

0 + 0 = 0

\frac{+ 1 2 1 2 0 0}{+ 0}

Add the digits of the bolded column:

1 + 2 = 3

\frac{+ 1 2 1 2 0 0}{+ 3 0}

Add the digits of the bolded column:

1 + 2 = 3

\frac{+ 1 2 1 2 0 0}{+ 3 3 0}

= 330

= 330

\frac{192}{32}

t o a p erce n t a g e 18/29

\frac{3}{7}

4, 10, 14

27 c d, 72