What is 10\div ((3-5)\times (2-4)+10\div (-3-2)) ?

The solution to 10\div ((3-5)\times (2-4)+10\div (-3-2)) is 5

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10\div ((3-5)\times (2-4)+10\div (-3-2))

10 \div ((3 - 5) \times (2 - 4) + 10 \div (- 3 - 2))

5

Solution steps

10 \div ((3 - 5) \times (2 - 4) + 10 \div (- 3 - 2))

Follow the PEMDAS order of operations

Calculate within parentheses

((3 - 5) \times (2 - 4) + 10 \div (- 3 - 2)) : 2

= 10 \div 2

Multiply and divide (left to right)

10 \div 2 : 5

= 5

\frac{99}{- 9 + 5 ^{2}}

2 - 3 \cdot [- 2 + 10 - 4 \cdot (- 1 + 3 \div 3) - 8] - 2

((- 8) - 6 - (- 4)) \div 5

5 - 4 \frac{3}{4} + \frac{1}{4}

36 \div 3 (8 - 6) \div 6

What is 10\div ((3-5)\times (2-4)+10\div (-3-2)) ?
The solution to 10\div ((3-5)\times (2-4)+10\div (-3-2)) is 5