What is -4+(-8+4)^3+6-3^2+4^3 ?

The solution to -4+(-8+4)^3+6-3^2+4^3 is -7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-4+(-8+4)^3+6-3^2+4^3

- 4 + (- 8 + 4)^{3} + 6 - 3^{2} + 4^{3}

- 7

Solution steps

- 4 + (- 8 + 4)^{3} + 6 - 3^{2} + 4^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8 + 4) : - 4

- 8 + 4

- 8 + 4 = - 4

= - 4

= - 4 + (- 4)^{3} + 6 - 3^{2} + 4^{3}

Calculate exponents

(- 4)^{3} : - 64

(- 4)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 4)^{3} = - 4^{3} = - 64

= - 64

= - 4 - 64 + 6 - 3^{2} + 4^{3}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 4 - 64 + 6 - 3^{2} + 4^{3}

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= - 4 - 64 + 6 - 3^{2} + 4^{3}

Add and subtract (left to right)

- 4 - 64 + 6 - 3^{2} + 4^{3} : - 7

- 4 - 64 + 6 - 3^{2} + 4^{3}

- 4 - 64 = - 68

= - 68 + 6 - 3^{2} + 4^{3}

- 68 + 6 = - 62

= - 62 - 3^{2} + 4^{3}

- 62 - 3^{2} = - 71

= - 71 + 4^{3}

- 71 + 4^{3} = - 7

= - 7

= - 7

- 3 - 2 [- 9 (5 - 4) - (- 6)]

1 - \frac{1}{4} - \frac{1}{3}

2 - \frac{7}{6} + \frac{3}{4}

3 (- 2)^{2} - 2 (- 2)

4^{2} \times 3^{2}