What is 3(4-5)^2+4(5-1)-3(1+2)^2(2)+2(3)(3) ?

The solution to 3(4-5)^2+4(5-1)-3(1+2)^2(2)+2(3)(3) is -17

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3(4-5)^2+4(5-1)-3(1+2)^2(2)+2(3)(3)

3 (4 - 5)^{2} + 4 (5 - 1) - 3 (1 + 2)^{2} (2) + 2 (3) (3)

- 17

Solution steps

3 (4 - 5)^{2} + 4 (5 - 1) - 3 (1 + 2)^{2} (2) + 2 (3) (3)

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 5) : - 1

4 - 5

4 - 5 = - 1

= - 1

= 3 (- 1)^{2} + 4 (5 - 1) - 3 (1 + 2)^{2} (2) + 2 (3) (3)

Calculate within parentheses

(5 - 1) : 4

5 - 1

5 - 1 = 4

= 4

= 3 (- 1)^{2} + 4 \cdot 4 - 3 (1 + 2)^{2} (2) + 2 (3) (3)

Calculate within parentheses

(1 + 2) : 3

1 + 2

1 + 2 = 3

= 3

= 3 (- 1)^{2} + 4 \cdot 4 - 3 \cdot 3^{2} (2) + 2 (3) (3)

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 3 \cdot 1 + 4 \cdot 4 - 3 \cdot 3^{2} (2) + 2 (3) (3)

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 3 \cdot 1 + 4 \cdot 4 - 3 \cdot 9 (2) + 2 (3) (3)

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 + 4 \cdot 4 - 3 \cdot 9 (2) + 2 (3) (3)

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 3 + 16 - 3 \cdot 9 (2) + 2 (3) (3)

Multiply and divide (left to right)

3 \cdot 9 (2) : 54

3 \cdot 9 (2)

3 \cdot 9 = 27

= 27 (2)

27 (2) = 54

27 (2)

Apply rule:

(a) = a

(2) = 2

= 27 \cdot 2

Multiply the numbers:

27 \cdot 2 = 54

= 54

= 54

= 3 + 16 - 54 + 2 (3) (3)

Multiply and divide (left to right)

2 (3) (3) : 18

2 (3) (3)

2 (3) = 6

2 (3)

Apply rule:

(a) = a

(3) = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= 6 (3)

6 (3) = 18

6 (3)

Apply rule:

(a) = a

(3) = 3

= 6 \cdot 3

Multiply the numbers:

6 \cdot 3 = 18

= 18

= 18

= 3 + 16 - 54 + 18

Add and subtract (left to right)

3 + 16 - 54 + 18 : - 17

3 + 16 - 54 + 18

3 + 16 = 19

= 19 - 54 + 18

19 - 54 = - 35

= - 35 + 18

- 35 + 18 = - 17

= - 17

= - 17

- 7^{2} + 4 (- 7) - 4

2 - 2^{2}

7^{2} + 1 5^{2}

3 + 90 \div 10

8 - [6 - (- 3 + 7) - 6] + 4

What is 3(4-5)^2+4(5-1)-3(1+2)^2(2)+2(3)(3) ?
The solution to 3(4-5)^2+4(5-1)-3(1+2)^2(2)+2(3)(3) is -17