What is 12+6^2+(-3)^4-8+9^2 ?

The solution to 12+6^2+(-3)^4-8+9^2 is 202

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12+6^2+(-3)^4-8+9^2

12 + 6^{2} + (- 3)^{4} - 8 + 9^{2}

202

Solution steps

12 + 6^{2} + (- 3)^{4} - 8 + 9^{2}

Follow the PEMDAS order of operations

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= 12 + 36 + (- 3)^{4} - 8 + 9^{2}

Calculate exponents

(- 3)^{4} : 81

(- 3)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{4} = 3^{4} = 81

= 81

= 12 + 36 + 81 - 8 + 9^{2}

Calculate exponents

9^{2} : 81

9^{2}

9^{2} = 81

= 81

= 12 + 36 + 81 - 8 + 81

Add and subtract (left to right)

12 + 36 + 81 - 8 + 81 : 202

12 + 36 + 81 - 8 + 81

12 + 36 = 48

= 48 + 81 - 8 + 81

48 + 81 = 129

= 129 - 8 + 81

129 - 8 = 121

= 121 + 81

121 + 81 = 202

= 202

= 202

- 7 - [(- 3) - (- 9)]

3 (7^{2} + 5) \div 6 - 3

2 - 3 (1)

3^{2} + (- 3)^{2}

\frac{5 ^{2} - 15}{10 - 2 ^{3}}