What is (3^2*(2^3+4))/(2^2) ?

The solution to (3^2*(2^3+4))/(2^2) is 27

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3^2*(2^3+4))/(2^2)

\frac{3 ^{2} \cdot ( 2 ^{3} + 4 )}{2 ^{2}}

27

Solution steps

\frac{3 ^{2} ( 2 ^{3} + 4 )}{2 ^{2}}

Solve

3^{2} \cdot (2^{3} + 4) : 108

Follow the PEMDAS order of operations

Calculate within parentheses

(2^{3} + 4) : 12

2^{3} + 4

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 + 4

Add and subtract (left to right)

8 + 4 : 12

8 + 4

8 + 4 = 12

= 12

= 12

= 3^{2} \cdot 12

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 \cdot 12

Multiply and divide (left to right)

9 \cdot 12 : 108

9 \cdot 12

9 \cdot 12 = 108

= 108

= 108

Solve

2^{2} : 4

2^{2} = 4

= 4

= \frac{108}{4}

Divide the numbers:

\frac{108}{4} = 27

= 27

2 + 1 \frac{2}{3} \times 2 \frac{2}{5}

4^{2} - 6

4^{2} + 5

(- 3 + 3)^{2}

4 (- 4)^{2} - 4