What is 13+(4^3\div 2)\times 5-17 ?

The solution to 13+(4^3\div 2)\times 5-17 is 156

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13+(4^3\div 2)\times 5-17

13 + (4^{3} \div 2) \times 5 - 17

156

Solution steps

13 + (4^{3} \div 2) \times 5 - 17

Follow the PEMDAS order of operations

Calculate within parentheses

(4^{3} \div 2) : 32

4^{3} \div 2

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= 64 \div 2

Multiply and divide (left to right)

64 \div 2 : 32

64 \div 2

64 \div 2 = 32

= 32

= 32

= 13 + 32 \times 5 - 17

Multiply and divide (left to right)

32 \times 5 : 160

32 \times 5

32 \times 5 = 160

= 160

= 13 + 160 - 17

Add and subtract (left to right)

13 + 160 - 17 : 156

13 + 160 - 17

13 + 160 = 173

= 173 - 17

173 - 17 = 156

= 156

= 156

(- 12) + (- 14) + (+ 18) + (- 2)

88 - 2 \cdot (36 - 13 + 7)

3^{4} \cdot 2

3^{3} - 5^{2}

(- 2) (- 3) (- 3) + (- 1)

What is 13+(4^3\div 2)\times 5-17 ?
The solution to 13+(4^3\div 2)\times 5-17 is 156