What is 4+2*[3+2-(4-1)] ?

The solution to 4+2*[3+2-(4-1)] is 8

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4+2*[3+2-(4-1)]

4 + 2 \cdot [3 + 2 - (4 - 1)]

8

Solution steps

4 + 2 [3 + 2 - (4 - 1)]

Follow the PEMDAS order of operations

Calculate within parentheses

[3 + 2 - (4 - 1)] : 2

3 + 2 - (4 - 1)

Calculate within parentheses

(4 - 1) : 3

4 - 1

4 - 1 = 3

= 3

= 3 + 2 - 3

Add and subtract (left to right)

3 + 2 - 3 : 2

3 + 2 - 3

3 + 2 = 5

= 5 - 3

5 - 3 = 2

= 2

= 2

= 4 + 2 \cdot 2

Multiply and divide (left to right)

2 \cdot 2 : 4

2 \cdot 2

2 \cdot 2 = 4

= 4

= 4 + 4

Add and subtract (left to right)

4 + 4 : 8

4 + 4

4 + 4 = 8

= 8

= 8

7.86 \cdot 4.6

3 + (- 4) - 8 - (- 1)

\frac{45}{60}

\frac{4}{8}

(7 + 5) + 4 \cdot 13 - 2