What is (-9)^2+9(-9) ?

The solution to (-9)^2+9(-9) is 0

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(-9)^2+9(-9)

(- 9)^{2} + 9 (- 9)

0

Solution steps

(- 9)^{2} + 9 (- 9)

Follow the PEMDAS order of operations

Calculate exponents

(- 9)^{2} : 81

(- 9)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 9)^{2} = 9^{2} = 81

= 81

= 81 + 9 (- 9)

Multiply and divide (left to right)

9 (- 9) : - 81

9 (- 9)

Apply rule

a \cdot (- b) = - a \cdot b

9 (- 9) = - 9 \cdot 9 = - 81

= - 81

= 81 - 81

Add and subtract (left to right)

81 - 81 : 0

81 - 81

81 - 81 = 0

= 0

= 0

1 - \frac{1}{3} - \frac{1}{4}

4 + (6^{2} \div \frac{1}{4}) \times 3

7^{2} + 1 4^{2}

(3) + 4 (2 + 12)

(- 5) (7) + 4 \times 5