What is 3(3)^2-4(3)-4 ?

The solution to 3(3)^2-4(3)-4 is 11

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3(3)^2-4(3)-4

3 (3)^{2} - 4 (3) - 4

11

Solution steps

3 (3)^{2} - 4 (3) - 4

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 3 \cdot 9 - 4 (3) - 4

Multiply and divide (left to right)

3 \cdot 9 : 27

3 \cdot 9

3 \cdot 9 = 27

= 27

= 27 - 4 (3) - 4

Multiply and divide (left to right)

4 (3) : 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 27 - 12 - 4

Add and subtract (left to right)

27 - 12 - 4 : 11

27 - 12 - 4

27 - 12 = 15

= 15 - 4

15 - 4 = 11

= 11

= 11

(- 3)^{2} + 6 (- 3) - 7

\frac{1}{2} - 2 - \frac{5}{6} + \frac{17}{3}

- 45 - (36 - 5 \cdot 7 + 3) \div 2

\frac{2 ^{30} + 2 ^{28}}{2 ^{28}}

(+ 5) \times (+ 11) - 37 - (- 2) \times (+ 14)