What is -(-4-1)^2+5 ?

The solution to -(-4-1)^2+5 is -20

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-(-4-1)^2+5

- (- 4 - 1)^{2} + 5

- 20

Solution steps

- (- 4 - 1)^{2} + 5

Follow the PEMDAS order of operations

Calculate within parentheses

(- 4 - 1) : - 5

- 4 - 1

- 4 - 1 = - 5

= - 5

= - (- 5)^{2} + 5

Calculate exponents

(- 5)^{2} : 25

(- 5)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2} = 25

= 25

= - 25 + 5

Add and subtract (left to right)

- 25 + 5 : - 20

- 25 + 5

- 25 + 5 = - 20

= - 20

= - 20

- 7 \cdot 3 \cdot (- 2) \cdot (- 5) \cdot (- 1)

\frac{12}{15}

150 + [(6 - 2) - (4 - 3)]

3^{2} - (- 3^{2})

1 - (1 + (1 - (1 + (1 - (1 + (1 - (1 + (1))))))))