What is (1)^2+2(1)-3 ?

The solution to (1)^2+2(1)-3 is 0

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(1)^2+2(1)-3

(1)^{2} + 2 (1) - 3

0

Solution steps

(1)^{2} + 2 (1) - 3

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 1 + 2 (1) - 3

Multiply and divide (left to right)

2 (1) : 2

2 (1)

Apply rule:

(a) = a

(1) = 1

= 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2

= 1 + 2 - 3

Add and subtract (left to right)

1 + 2 - 3 : 0

1 + 2 - 3

1 + 2 = 3

= 3 - 3

3 - 3 = 0

= 0

= 0

(\frac{1}{2} - \frac{3}{2}) - \frac{4}{4}

(- 5 + 7 \times 1) - 9 \times 5

3^{2} \times 2^{3}

2 \div 3 (3 \div 13) - 1

5 \cdot 3^{2} - 3 + 9