What is 4^3(2)\div 2(4)-(8-3+2)-7 ?

The solution to 4^3(2)\div 2(4)-(8-3+2)-7 is 242

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4^3(2)\div 2(4)-(8-3+2)-7

4^{3} (2) \div 2 (4) - (8 - 3 + 2) - 7

242

Solution steps

4^{3} (2) \div 2 (4) - (8 - 3 + 2) - 7

Follow the PEMDAS order of operations

Calculate within parentheses

(8 - 3 + 2) : 7

8 - 3 + 2

Add and subtract (left to right)

8 - 3 = 5

= 5 + 2

5 + 2 = 7

= 7

= 4^{3} (2) \div 2 (4) - 7 - 7

Calculate exponents

4^{3} : 64

4^{3}

4^{3} = 64

= 64

= 64 (2) \div 2 (4) - 7 - 7

Multiply and divide (left to right)

64 (2) \div 2 (4) : 256

64 (2) \div 2 (4)

64 (2) = 128

64 (2)

Apply rule:

(a) = a

(2) = 2

= 64 \cdot 2

Multiply the numbers:

64 \cdot 2 = 128

= 128

= 128 \div 2 (4)

128 \div 2 = 64

= 64 (4)

64 (4) = 256

64 (4)

Apply rule:

(a) = a

(4) = 4

= 64 \cdot 4

Multiply the numbers:

64 \cdot 4 = 256

= 256

= 256

= 256 - 7 - 7

Add and subtract (left to right)

256 - 7 - 7 : 242

256 - 7 - 7

256 - 7 = 249

= 249 - 7

249 - 7 = 242

= 242

= 242

- 2 + 3 (1 - 4) - 2

18 - (21 - 5) \div (22 - 18)

8 \times \frac{15}{5} - (5 + 9)

3 6^{2} - 3 4^{2}

13 + 7 - 3^{2}

What is 4^3(2)\div 2(4)-(8-3+2)-7 ?
The solution to 4^3(2)\div 2(4)-(8-3+2)-7 is 242