What is (2^2-16)/(2-4) ?

The solution to (2^2-16)/(2-4) is 6

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(2^2-16)/(2-4)

\frac{2 ^{2} - 16}{2 - 4}

6

Solution steps

\frac{2 ^{2} - 16}{2 - 4}

Solve

2^{2} - 16 : - 12

Follow the PEMDAS order of operations

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 - 16

Add and subtract (left to right)

4 - 16 : - 12

4 - 16

4 - 16 = - 12

= - 12

= - 12

Solve

2 - 4 : - 2

2 - 4 = - 2

= - 2

= \frac{- 12}{- 2}

Simplify

\frac{- 12}{- 2} : 6

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{12}{2}

Divide the numbers:

\frac{12}{2} = 6

= 6

= 6

- 4 - 3 \times (- 2)

(\frac{1}{2} \div 2) \div 4

1 - (- 3 + 6 + 1) - [4 - (6 - 3 + 1) - 2]

(- 2)^{2} + 7

5 + 6 \cdot (- 3) + (- 4)^{2}