What is (-6)^2-4\times 1\times (16) ?

The solution to (-6)^2-4\times 1\times (16) is -28

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(-6)^2-4\times 1\times (16)

(- 6)^{2} - 4 \cdot 1 \cdot (16)

- 28

Solution steps

(- 6)^{2} - 4 \cdot 1 \cdot (16)

Follow the PEMDAS order of operations

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= 36 - 4 \cdot 1 \cdot (16)

Multiply and divide (left to right)

4 \cdot 1 \cdot (16) : 64

4 \cdot 1 \cdot (16)

4 \cdot 1 = 4

= 4 (16)

4 \cdot (16) = 64

4 (16)

Apply rule:

(a) = a

(16) = 16

= 4 \cdot 16

Multiply the numbers:

4 \cdot 16 = 64

= 64

= 64

= 36 - 64

Add and subtract (left to right)

36 - 64 : - 28

36 - 64

36 - 64 = - 28

= - 28

= - 28

- 4 + (- 12) + (- 6)

2 + 5 (44 - 1)

(5 + 2) 3

4^{2} - 9 (4) + 8

5^{3} + 5^{2}

What is (-6)^2-4\times 1\times (16) ?
The solution to (-6)^2-4\times 1\times (16) is -28