The solution to 3/4 (2)-1 is 1/2

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3/4 (2)-1

Solution

\frac{3}{4} (2) - 1

\frac{1}{2}

Solution steps

\frac{3}{4} (2) - 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{3}{4} (2) : \frac{3}{2}

\frac{3}{4} (2)

Apply rule:

(a) = a

(2) = 2

= \frac{3}{4} \cdot 2

\frac{3}{4} \cdot 2 = \frac{3}{2}

\frac{3}{4} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= \frac{3}{4} \cdot \frac{2}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 2}{4 \cdot 1}

\frac{3 \cdot 2}{4 \cdot 1} = \frac{3}{2}

\frac{3 \cdot 2}{4 \cdot 1}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{3 \cdot 2}{4}

Factor the number:

4 = 2 \cdot 2

= \frac{3 \cdot 2}{2 \cdot 2}

Cancel the common factor:

2

= \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2}

= \frac{3}{2} - 1

Add and subtract (left to right)

\frac{3}{2} - 1 : \frac{1}{2}

\frac{3}{2} - 1

\frac{3}{2} - 1 = \frac{1}{2}

\frac{3}{2} - 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} + \frac{3}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 + 3}{2}

- 1 \cdot 2 + 3 = 1

- 1 \cdot 2 + 3

Multiply the numbers:

1 \cdot 2 = 2

= - 2 + 3

Add/Subtract the numbers:

- 2 + 3 = 1

= 1

= \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

48 - 8 + 31 - 9 + 7 - 9 - 8

2 (4) + 1

5 ([(12 - 2) \times (5 - 3) + (8 - 12 + 11)] - 10)

4 (2) + 5

- 7 \frac{4}{5} + (- 1) \frac{1}{5}