What is (14^2\times 15)-(2^2+20) ?

The solution to (14^2\times 15)-(2^2+20) is 2916

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(14^2\times 15)-(2^2+20)

(1 4^{2} \cdot 15) - (2^{2} + 20)

2916

Solution steps

(1 4^{2} \cdot 15) - (2^{2} + 20)

Follow the PEMDAS order of operations

Calculate within parentheses

(1 4^{2} \cdot 15) : 2940

1 4^{2} \cdot 15

Calculate exponents

1 4^{2} : 196

1 4^{2}

1 4^{2} = 196

= 196

= 196 \cdot 15

Multiply and divide (left to right)

196 \cdot 15 : 2940

196 \cdot 15

196 \cdot 15 = 2940

= 2940

= 2940

= 2940 - (2^{2} + 20)

Calculate within parentheses

(2^{2} + 20) : 24

2^{2} + 20

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 + 20

Add and subtract (left to right)

4 + 20 : 24

4 + 20

4 + 20 = 24

= 24

= 24

= 2940 - 24

Add and subtract (left to right)

2940 - 24 : 2916

2940 - 24

2940 - 24 = 2916

= 2916

= 2916

3^{2} - (- 2^{2})

4^{3} \cdot 5^{3}

2 + 1 \div 2

4 \times (12 \times 6 - 4^{2}) + 9

(6 \cdot 6)^{0}

What is (14^2\times 15)-(2^2+20) ?
The solution to (14^2\times 15)-(2^2+20) is 2916