What is 7-12+(-3)\div (-3)\times 6\div (-9) ?

The solution to 7-12+(-3)\div (-3)\times 6\div (-9) is -17/3

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7-12+(-3)\div (-3)\times 6\div (-9)

7 - 12 + (- 3) \div (- 3) \times 6 \div (- 9)

- \frac{17}{3}

Solution steps

7 - 12 + (- 3) \div (- 3) \times 6 \div (- 9)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

(- 3) \div (- 3) \times 6 \div (- 9) : \frac{6}{( - 9 )}

(- 3) \div (- 3) \times 6 \div (- 9)

Apply rule

(- a) \div (- b) = a \div b

(- 3) \div (- 3) = 3 \div 3 = 1

= 1 \times 6 \div (- 9)

1 \times 6 = 6

= 6 \div (- 9)

Apply rule

a \div (- b) = - a \div b

6 \div (- 9) = - 6 \div 9 = \frac{6}{( - 9 )}

= \frac{6}{( - 9 )}

= 7 - 12 + \frac{6}{( - 9 )}

Add and subtract (left to right)

7 - 12 + \frac{6}{( - 9 )} : - \frac{17}{3}

7 - 12 + \frac{6}{( - 9 )}

7 - 12 = - 5

= - 5 + \frac{6}{( - 9 )}

- 5 + \frac{6}{( - 9 )} = - \frac{17}{3}

- 5 + \frac{6}{- 9}

\frac{6}{- 9} = - \frac{2}{3}

\frac{6}{- 9}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{6}{9}

Cancel the common factor:

3

= - \frac{2}{3}

= - 5 - \frac{2}{3}

Convert element to fraction:

5 = \frac{5 \cdot 3}{3}

= - \frac{5 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 5 \cdot 3 - 2}{3}

- 5 \cdot 3 - 2 = - 17

- 5 \cdot 3 - 2

Multiply the numbers:

5 \cdot 3 = 15

= - 15 - 2

Subtract the numbers:

- 15 - 2 = - 17

= - 17

= \frac{- 17}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{17}{3}

= - \frac{17}{3}

= - \frac{17}{3}

3 (1) - 2 (1)^{2} + 1

4 + \frac{2}{3} - 2 \frac{1}{4}

(- 4) \times (- 4) \times (- 4)

- 2^{2} + 2 (- 2) + 4

12 6^{2} - 7 4^{2}

What is 7-12+(-3)\div (-3)\times 6\div (-9) ?
The solution to 7-12+(-3)\div (-3)\times 6\div (-9) is -17/3