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Popular >

8/3-8+6

Solution

\frac{8}{3} - 8 + 6

\frac{2}{3}

Solution steps

\frac{8}{3} - 8 + 6

Follow the PEMDAS order of operations

Add and subtract (left to right)

\frac{8}{3} - 8 = - \frac{16}{3}

\frac{8}{3} - 8

Convert element to fraction:

8 = \frac{8 \cdot 3}{3}

= - \frac{8 \cdot 3}{3} + \frac{8}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 8 \cdot 3 + 8}{3}

- 8 \cdot 3 + 8 = - 16

- 8 \cdot 3 + 8

Multiply the numbers:

8 \cdot 3 = 24

= - 24 + 8

Add/Subtract the numbers:

- 24 + 8 = - 16

= - 16

= \frac{- 16}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{16}{3}

= - \frac{16}{3} + 6

- \frac{16}{3} + 6 = \frac{2}{3}

- \frac{16}{3} + 6

Convert element to fraction:

6 = \frac{6 \cdot 3}{3}

= \frac{6 \cdot 3}{3} - \frac{16}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{6 \cdot 3 - 16}{3}

6 \cdot 3 - 16 = 2

6 \cdot 3 - 16

Multiply the numbers:

6 \cdot 3 = 18

= 18 - 16

Subtract the numbers:

18 - 16 = 2

= 2

= \frac{2}{3}

= \frac{2}{3}

2^{5} \cdot 3^{3}

6^{2} - 7 (8 + 6 - 3^{2})

1 7^{2} + 1 5^{2}

3 (- 1)^{1} + 5 - 1

- 3 - 8 + 5