What is 8-(-7)^2(4+3)-(4-5) ?

The solution to 8-(-7)^2(4+3)-(4-5) is -334

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8-(-7)^2(4+3)-(4-5)

8 - (- 7)^{2} (4 + 3) - (4 - 5)

- 334

Solution steps

8 - (- 7)^{2} (4 + 3) - (4 - 5)

Follow the PEMDAS order of operations

Calculate within parentheses

(4 + 3) : 7

4 + 3

4 + 3 = 7

= 7

= 8 - (- 7)^{2} \cdot 7 - (4 - 5)

Calculate within parentheses

(4 - 5) : - 1

4 - 5

4 - 5 = - 1

= - 1

= 8 - (- 7)^{2} \cdot 7 - (- 1)

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 8 - 49 \cdot 7 - (- 1)

Multiply and divide (left to right)

49 \cdot 7 : 343

49 \cdot 7

49 \cdot 7 = 343

= 343

= 8 - 343 - (- 1)

Add and subtract (left to right)

8 - 343 - (- 1) : - 334

8 - 343 - (- 1)

8 - 343 = - 335

= - 335 - (- 1)

Apply rule

- (- a) = + a

- (- 1) = + 1

= - 335 + 1

- 335 + 1 = - 334

= - 334

= - 334

3 3^{2} + 5 6^{2}

- (- (- (- 7 + 8 - 9 + \frac{10}{10} - 3) - 8) - 10 - 3)

\frac{1}{2} \cdot 2^{0} - 4

- 2 (2) - 2

(+ 3) + (- 5) + (+ 8) + (+ 5)