What is (-2)^2+5(-2)+1 ?

The solution to (-2)^2+5(-2)+1 is -5

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(-2)^2+5(-2)+1

(- 2)^{2} + 5 (- 2) + 1

- 5

Solution steps

(- 2)^{2} + 5 (- 2) + 1

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 5 (- 2) + 1

Multiply and divide (left to right)

5 (- 2) : - 10

5 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 2) = - 5 \cdot 2 = - 10

= - 10

= 4 - 10 + 1

Add and subtract (left to right)

4 - 10 + 1 : - 5

4 - 10 + 1

4 - 10 = - 6

= - 6 + 1

- 6 + 1 = - 5

= - 5

= - 5

3 \cdot [- 3 + (- 3)] - 14 \div (- 7)

\times (\times (- 2))

- 3 (3) - 2

(- 8 - 3 - 9) + 4 + (- 2 + 9)

\frac{- 2}{- 2 ^{2} + 1}