What is 4(-2)^2+8(-2)+3(-2)+6 ?

The solution to 4(-2)^2+8(-2)+3(-2)+6 is 0

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4(-2)^2+8(-2)+3(-2)+6

4 (- 2)^{2} + 8 (- 2) + 3 (- 2) + 6

0

Solution steps

4 (- 2)^{2} + 8 (- 2) + 3 (- 2) + 6

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 \cdot 4 + 8 (- 2) + 3 (- 2) + 6

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 16 + 8 (- 2) + 3 (- 2) + 6

Multiply and divide (left to right)

8 (- 2) : - 16

8 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

8 (- 2) = - 8 \cdot 2 = - 16

= - 16

= 16 - 16 + 3 (- 2) + 6

Multiply and divide (left to right)

3 (- 2) : - 6

3 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 2) = - 3 \cdot 2 = - 6

= - 6

= 16 - 16 - 6 + 6

Add and subtract (left to right)

16 - 16 - 6 + 6 : 0

16 - 16 - 6 + 6

16 - 16 = 0

= 0 - 6 + 6

0 - 6 = - 6

= - 6 + 6

- 6 + 6 = 0

= 0

= 0

\frac{16}{25}

(2 - 3)^{2}

2.5 \cdot 2.5

\frac{( 8 ^{2} - 2 ^{5} )}{( \frac{24}{6} )} + 3^{2}

3 \cdot 2^{4} - 16 \cdot 2^{3} + 24 \cdot 4 - 10