What is (3*2^9+6*2^5)/(12^3) ?

The solution to (3*2^9+6*2^5)/(12^3) is 1

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(32^9+62^5)/(12^3)

\frac{3 \cdot 2 ^{9} + 6 \cdot 2 ^{5}}{1 2 ^{3}}

1

Solution steps

\frac{3 \cdot 2 ^{9} + 6 \cdot 2 ^{5}}{1 2 ^{3}}

Solve

3 \cdot 2^{9} + 6 \cdot 2^{5} : 1728

Follow the PEMDAS order of operations

Calculate exponents

2^{9} : 512

2^{9}

2^{9} = 512

= 512

= 3 \cdot 512 + 6 \cdot 2^{5}

Calculate exponents

2^{5} : 32

2^{5}

2^{5} = 32

= 32

= 3 \cdot 512 + 6 \cdot 32

Multiply and divide (left to right)

3 \cdot 512 : 1536

3 \cdot 512

3 \cdot 512 = 1536

= 1536

= 1536 + 6 \cdot 32

Multiply and divide (left to right)

6 \cdot 32 : 192

6 \cdot 32

6 \cdot 32 = 192

= 192

= 1536 + 192

Add and subtract (left to right)

1536 + 192 : 1728

1536 + 192

1536 + 192 = 1728

= 1728

= 1728

Solve

1 2^{3} : 1728

1 2^{3} = 1728

= 1728

= \frac{1728}{1728}

Apply rule

\frac{a}{a} = 1

= 1

7 - (7 + 2) \div 3

17 - 3 \times (8 - 4) + 54 \div 2

10 \cdot [- 2 + 4 \cdot (3 - 5 \cdot 2)]

(1 0^{2} \div (6 + 8 - 9)^{2}) \times 4

+ (- 7 - (8 - 9 - 11 - 9 + 20 - 7) - 7 + 8 - 1) - 7