What is 1/10 \times (2 3/7-1) ?

The solution to 1/10 \times (2 3/7-1) is 1/7

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1/10 \times (2 3/7-1)

\frac{1}{10} \cdot (2 \frac{3}{7} - 1)

\frac{1}{7}

Solution steps

\frac{1}{10} \cdot (2 \frac{3}{7} - 1)

Convert mixed numbers to improper fractions:

2 \frac{3}{7} = \frac{17}{7}

2 \frac{3}{7}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{3}{7} = \frac{2 \cdot 7 + 3}{7}

= \frac{17}{7}

= \frac{1}{10} \cdot (\frac{17}{7} - 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{17}{7} - 1) : \frac{10}{7}

\frac{17}{7} - 1

\frac{17}{7} - 1 = \frac{10}{7}

\frac{17}{7} - 1

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= - \frac{1 \cdot 7}{7} + \frac{17}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 7 + 17}{7}

- 1 \cdot 7 + 17 = 10

- 1 \cdot 7 + 17

Multiply the numbers:

1 \cdot 7 = 7

= - 7 + 17

Add/Subtract the numbers:

- 7 + 17 = 10

= 10

= \frac{10}{7}

= \frac{10}{7}

= \frac{1}{10} \cdot \frac{10}{7}

Multiply and divide (left to right)

\frac{1}{10} \cdot \frac{10}{7} : \frac{1}{7}

\frac{1}{10} \cdot \frac{10}{7}

\frac{1}{10} \cdot \frac{10}{7} = \frac{1}{7}

= \frac{1}{7}

= \frac{1}{7}

2 (- 4)^{3} + 6

2^{5} - 5^{2}

854 \div 1 0^{3}

2^{6} + 1

5^{3} + 6^{3}