What is 4(-1)^3-12(-1)^2 ?

The solution to 4(-1)^3-12(-1)^2 is -16

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4(-1)^3-12(-1)^2

4 (- 1)^{3} - 12 (- 1)^{2}

- 16

Solution steps

4 (- 1)^{3} - 12 (- 1)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= 4 (- 1) - 12 (- 1)^{2}

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 4 (- 1) - 12 \cdot 1

Multiply and divide (left to right)

4 (- 1) : - 4

4 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 1) = - 4 \cdot 1 = - 4

= - 4

= - 4 - 12 \cdot 1

Multiply and divide (left to right)

12 \cdot 1 : 12

12 \cdot 1

12 \cdot 1 = 12

= 12

= - 4 - 12

Add and subtract (left to right)

- 4 - 12 : - 16

- 4 - 12

- 4 - 12 = - 16

= - 16

= - 16

(6 + 5 + 4) 3

- 2 - 3 + 5

(4 \times 3 + 6) - (2 \times 8 + 16) + (6)^{3}

100 - (4 + 20 \div 5)

\frac{3 ( 4 ) ^{2}}{2}