What is 1/5 (6+3+1)^2 ?

The solution to 1/5 (6+3+1)^2 is 20

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1/5 (6+3+1)^2

\frac{1}{5} (6 + 3 + 1)^{2}

20

Solution steps

\frac{1}{5} (6 + 3 + 1)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(6 + 3 + 1) : 10

6 + 3 + 1

6 + 3 + 1 = 10

= 10

= \frac{1}{5} \cdot 1 0^{2}

Calculate exponents

1 0^{2} : 100

1 0^{2}

1 0^{2} = 100

= 100

= \frac{1}{5} \cdot 100

Multiply and divide (left to right)

\frac{1}{5} \cdot 100 : 20

\frac{1}{5} \cdot 100

Convert element to fraction:

100 = \frac{100}{1}

= \frac{1}{5} \cdot \frac{100}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 100}{5 \cdot 1}

\frac{1 \cdot 100}{5 \cdot 1} = 20

\frac{1 \cdot 100}{5 \cdot 1}

\frac{1 \cdot 100}{5 \cdot 1} = \frac{100}{5}

\frac{1 \cdot 100}{5 \cdot 1}

Multiply the numbers:

1 \cdot 100 = 100

= \frac{100}{5 \cdot 1}

Multiply the numbers:

5 \cdot 1 = 5

= \frac{100}{5}

= \frac{100}{5}

Divide the numbers:

\frac{100}{5} = 20

= 20

= 20

= 20

+ 10 - 30 - 20 - 80

10 - (- 8 - 5 + 4 + (- 3 - 5))

9 6^{2} + 4 0^{2}

(9 - 3) (912)

- (2 - 4)^{2} \times 3 - 4 \times 2