What is (-4)^2+5(-4)+6 ?

The solution to (-4)^2+5(-4)+6 is 2

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(-4)^2+5(-4)+6

(- 4)^{2} + 5 (- 4) + 6

2

Solution steps

(- 4)^{2} + 5 (- 4) + 6

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= 16 + 5 (- 4) + 6

Multiply and divide (left to right)

5 (- 4) : - 20

5 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 4) = - 5 \cdot 4 = - 20

= - 20

= 16 - 20 + 6

Add and subtract (left to right)

16 - 20 + 6 : 2

16 - 20 + 6

16 - 20 = - 4

= - 4 + 6

- 4 + 6 = 2

= 2

= 2

- 1 - 1 - 7

2 5^{2} + {4 \times 5 (8 - 5) + 4}

7 + 5 \times 3 - (1 \times 5 + 16) \div 8 + (4 \times 2)

9 - 5 \times 8 + (54 \div 6 - 5) - (3 - 12)

4^{3} + 2^{3}