What is (9(14-8)+6)/(7^2-29) ?

The solution to (9(14-8)+6)/(7^2-29) is 3

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(9(14-8)+6)/(7^2-29)

\frac{9 ( 14 - 8 ) + 6}{7 ^{2} - 29}

3

Solution steps

\frac{9 ( 14 - 8 ) + 6}{7 ^{2} - 29}

Solve

9 (14 - 8) + 6 : 60

Follow the PEMDAS order of operations

Calculate within parentheses

(14 - 8) : 6

14 - 8

14 - 8 = 6

= 6

= 9 \cdot 6 + 6

Multiply and divide (left to right)

9 \cdot 6 : 54

9 \cdot 6

9 \cdot 6 = 54

= 54

= 54 + 6

Add and subtract (left to right)

54 + 6 : 60

54 + 6

54 + 6 = 60

= 60

= 60

Solve

7^{2} - 29 : 20

Follow the PEMDAS order of operations

Calculate exponents

7^{2} : 49

7^{2}

7^{2} = 49

= 49

= 49 - 29

Add and subtract (left to right)

49 - 29 : 20

49 - 29

49 - 29 = 20

= 20

= 20

= \frac{60}{20}

Divide the numbers:

\frac{60}{20} = 3

= 3

+ 13 - 43 - 5 - 6 + 17 + 2

(1)^{2} + 9

2^{4} - (2)^{3} - 3 (2)^{2} + 7 (2) - 10

10 \times 5 - (- 6)^{2} + (- 8)

3 [2 - 4 (7 - 12)]