What is (1\div 8)+(1\div 4) ?

The solution to (1\div 8)+(1\div 4) is 3/8

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(1\div 8)+(1\div 4)

(1 \div 8) + (1 \div 4)

\frac{3}{8}

Solution steps

(1 \div 8) + (1 \div 4)

Follow the PEMDAS order of operations

Calculate within parentheses

(1 \div 8) : \frac{1}{8}

1 \div 8

1 \div 8 = \frac{1}{8}

= \frac{1}{8}

= \frac{1}{8} + (1 \div 4)

Calculate within parentheses

(1 \div 4) : \frac{1}{4}

1 \div 4

1 \div 4 = \frac{1}{4}

= \frac{1}{4}

= \frac{1}{8} + \frac{1}{4}

Add and subtract (left to right)

\frac{1}{8} + \frac{1}{4} : \frac{3}{8}

\frac{1}{8} + \frac{1}{4}

\frac{1}{8} + \frac{1}{4} = \frac{3}{8}

\frac{1}{8} + \frac{1}{4}

Least Common Multiplier of

8, 4 : 8

8, 4

Least Common Multiplier (LCM)

Prime factorization of

8 : 2 \cdot 2 \cdot 2

8

8

divides by

28 = 4 \cdot 2

= 2 \cdot 4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2 \cdot 2

Prime factorization of

4 : 2 \cdot 2

4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2

Multiply each factor the greatest number of times it occurs in either

8

4

= 2 \cdot 2 \cdot 2

Multiply the numbers:

2 \cdot 2 \cdot 2 = 8

= 8

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

8

For

\frac{1}{4} :

multiply the denominator and numerator by

2

\frac{1}{4} = \frac{1 \cdot 2}{4 \cdot 2} = \frac{2}{8}

= \frac{1}{8} + \frac{2}{8}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 2}{8}

Add the numbers:

1 + 2 = 3

= \frac{3}{8}

= \frac{3}{8}

= \frac{3}{8}

- 21 (20) + 17

3 1^{2} - 13

7 + 5 \cdot 3^{2} - 4 \cdot 8

- 3 \div 2 + 1

4 - 6 \times 2 \div 2 + 2