What is 2-(-2)^3+(-3)^0+2 ?

The solution to 2-(-2)^3+(-3)^0+2 is 13

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2-(-2)^3+(-3)^0+2

2 - (- 2)^{3} + (- 3)^{0} + 2

13

Solution steps

2 - (- 2)^{3} + (- 3)^{0} + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 2 - (- 8) + (- 3)^{0} + 2

Calculate exponents

(- 3)^{0} : 1

(- 3)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{0} = 3^{0} = 1

= 1

= 2 - (- 8) + 1 + 2

Add and subtract (left to right)

2 - (- 8) + 1 + 2 : 13

2 - (- 8) + 1 + 2

Apply rule

- (- a) = + a

- (- 8) = + 8

= 2 + 8 + 1 + 2

2 + 8 = 10

= 10 + 1 + 2

10 + 1 = 11

= 11 + 2

11 + 2 = 13

= 13

= 13

4 \div 15 \div 5

(- 14)^{2} - 17 (14) + 72

(0)^{2} + 5

(- 5)^{2} + (- 5)^{2}

- 6 \frac{2}{5} \times 3 \div 2 \frac{2}{4}