The solution to 1/2 (1)-3 is -5/2

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1/2 (1)-3

Solution

\frac{1}{2} (1) - 3

- \frac{5}{2}

Solution steps

\frac{1}{2} (1) - 3

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{1}{2} (1) : \frac{1}{2}

\frac{1}{2} (1)

Apply rule:

(a) = a

(1) = 1

= \frac{1}{2} \cdot 1

Multiply the numbers:

\frac{1}{2} \cdot 1 = \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2} - 3

Add and subtract (left to right)

\frac{1}{2} - 3 : - \frac{5}{2}

\frac{1}{2} - 3

\frac{1}{2} - 3 = - \frac{5}{2}

\frac{1}{2} - 3

Convert element to fraction:

3 = \frac{3 \cdot 2}{2}

= - \frac{3 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 2 + 1}{2}

- 3 \cdot 2 + 1 = - 5

- 3 \cdot 2 + 1

Multiply the numbers:

3 \cdot 2 = 6

= - 6 + 1

Add/Subtract the numbers:

- 6 + 1 = - 5

= - 5

= \frac{- 5}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{5}{2}

= - \frac{5}{2}

= - \frac{5}{2}

(- 2)^{2} + 9 (- 2) - 8

1 \frac{5}{12} - (\frac{1}{6} + \frac{3}{4})

(\frac{3}{8} + \frac{1}{4}) \cdot 16

2 4^{2} + 3 0^{2}

7 - 9 \div 9 + 4 (4 - 3) - 7