What is 1+(2/7 \times (-2)) ?

The solution to 1+(2/7 \times (-2)) is 3/7

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1+(2/7 \times (-2))

1 + (\frac{2}{7} \cdot (- 2))

\frac{3}{7}

Solution steps

1 + (\frac{2}{7} (- 2))

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{2}{7} \cdot (- 2)) : - \frac{4}{7}

\frac{2}{7} (- 2)

Multiply and divide (left to right)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{2}{7} (- 2) = - \frac{2}{7} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{2}{7} \cdot \frac{2}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{2}{7} \cdot \frac{2}{1} = \frac{2 \cdot 2}{7 \cdot 1}

= - \frac{2 \cdot 2}{7 \cdot 1}

Multiply the numbers:

2 \cdot 2 = 4

= - \frac{4}{7 \cdot 1}

Multiply the numbers:

7 \cdot 1 = 7

= - \frac{4}{7}

= 1 - \frac{4}{7}

Add and subtract (left to right)

1 - \frac{4}{7} : \frac{3}{7}

1 - \frac{4}{7}

1 - \frac{4}{7} = \frac{3}{7}

1 - \frac{4}{7}

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= \frac{1 \cdot 7}{7} - \frac{4}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 7 - 4}{7}

1 \cdot 7 - 4 = 3

1 \cdot 7 - 4

Multiply the numbers:

1 \cdot 7 = 7

= 7 - 4

Subtract the numbers:

7 - 4 = 3

= 3

= \frac{3}{7}

= \frac{3}{7}

= \frac{3}{7}

1 - 1 + 1 - 1

5^{2} \times 6

7^{2} - 2 [3 + 2 (5 - 1)]

\frac{( - 6 ) - ( + 6 )}{( - 2 ) ^{2}}

3 \times (5 + 3 \times 2) - (8 \times 5) - 3