What is (-2)^2\div (-3)^3 ?

The solution to (-2)^2\div (-3)^3 is -4/27

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(-2)^2\div (-3)^3

(- 2)^{2} \div (- 3)^{3}

- \frac{4}{27}

Solution steps

(- 2)^{2} \div (- 3)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 \div (- 3)^{3}

Calculate exponents

(- 3)^{3} : - 27

(- 3)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3)^{3} = - 3^{3} = - 27

= - 27

= 4 \div (- 27)

Multiply and divide (left to right)

4 \div (- 27) : \frac{4}{( - 27 )}

4 \div (- 27)

Apply rule

a \div (- b) = - a \div b

4 \div (- 27) = - 4 \div 27 = \frac{4}{( - 27 )}

= \frac{4}{( - 27 )}

= \frac{4}{( - 27 )}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{4}{27}

10 \cdot 12 - 14 \div 2 + 15

2 + (- \frac{2}{315}) - \frac{2}{5}

- (- 3)^{2} - 5 (- 3) + 1

0 + 5 - 3 + 5 - 8 + 10 + 5 - 6

(- 4)^{2} + 5 (- 4) - 6