What is -5^2-2\times (2)\times (-5)+2^2 ?

The solution to -5^2-2\times (2)\times (-5)+2^2 is -1

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-5^2-2\times (2)\times (-5)+2^2

- 5^{2} - 2 \cdot (2) \cdot (- 5) + 2^{2}

- 1

Solution steps

- 5^{2} - 2 (2) (- 5) + 2^{2}

Follow the PEMDAS order of operations

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= - 25 - 2 (2) (- 5) + 2^{2}

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= - 25 - 2 (2) (- 5) + 4

Multiply and divide (left to right)

2 (2) (- 5) : - 20

2 (2) (- 5)

2 \cdot (2) = 4

2 (2)

Apply rule:

(a) = a

(2) = 2

= 2 \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 4

= 4 (- 5)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 5) = - 4 \cdot 5 = - 20

= - 20

= - 25 - (- 20) + 4

Add and subtract (left to right)

- 25 - (- 20) + 4 : - 1

- 25 - (- 20) + 4

Apply rule

- (- a) = + a

- (- 20) = + 20

= - 25 + 20 + 4

- 25 + 20 = - 5

= - 5 + 4

- 5 + 4 = - 1

= - 1

= - 1

(- 40 + 4) \div (- 4)

(9 + 3)^{2}

- 2 + 8 - 4 + 13 - 6

11 (11 \times 10 + 3 \times 12 + 8)

25 \div 5 + 36 \div 6 + 49 \div 7

What is -5^2-2\times (2)\times (-5)+2^2 ?
The solution to -5^2-2\times (2)\times (-5)+2^2 is -1