What is 1\times 4-(3-6+2)-5\times (-3) ?

The solution to 1\times 4-(3-6+2)-5\times (-3) is 20

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1\times 4-(3-6+2)-5\times (-3)

1 \cdot 4 - (3 - 6 + 2) - 5 \cdot (- 3)

20

Solution steps

1 \cdot 4 - (3 - 6 + 2) - 5 (- 3)

Follow the PEMDAS order of operations

Calculate within parentheses

(3 - 6 + 2) : - 1

3 - 6 + 2

Add and subtract (left to right)

3 - 6 = - 3

= - 3 + 2

- 3 + 2 = - 1

= - 1

= 1 \cdot 4 - (- 1) - 5 (- 3)

Multiply and divide (left to right)

1 \cdot 4 : 4

1 \cdot 4

1 \cdot 4 = 4

= 4

= 4 - (- 1) - 5 (- 3)

Multiply and divide (left to right)

5 (- 3) : - 15

5 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 3) = - 5 \cdot 3 = - 15

= - 15

= 4 - (- 1) - (- 15)

Add and subtract (left to right)

4 - (- 1) - (- 15) : 20

4 - (- 1) - (- 15)

Apply rule

- (- a) = + a

- (- 1) = + 1

= 4 + 1 - (- 15)

4 + 1 = 5

= 5 - (- 15)

Apply rule

- (- a) = + a

- (- 15) = + 15

= 5 + 15

5 + 15 = 20

= 20

= 20

(4 - 2) \cdot 180

20 \div 2 + 3

(1)^{2} - 5 (1) + 1

1 - (2 \times 0)

3 (3)^{2} - 3

What is 1\times 4-(3-6+2)-5\times (-3) ?
The solution to 1\times 4-(3-6+2)-5\times (-3) is 20