What is 2{4[7+4(5*3-9)]-3(40-8)} ?

The solution to 2{4[7+4(5*3-9)]-3(40-8)} is 56

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2{4[7+4(5*3-9)]-3(40-8)}

2 {4 [7 + 4 (5 \cdot 3 - 9)] - 3 (40 - 8)}

56

Solution steps

2 {4 [7 + 4 (5 \cdot 3 - 9)] - 3 (40 - 8)}

Follow the PEMDAS order of operations

Calculate within parentheses

{4 [7 + 4 (5 \cdot 3 - 9)] - 3 (40 - 8)} : 28

4 [7 + 4 (5 \cdot 3 - 9)] - 3 (40 - 8)

Calculate within parentheses

[7 + 4 (5 \cdot 3 - 9)] : 31

7 + 4 (5 \cdot 3 - 9)

Calculate within parentheses

(5 \cdot 3 - 9) : 6

5 \cdot 3 - 9

Multiply and divide (left to right)

5 \cdot 3 : 15

5 \cdot 3

5 \cdot 3 = 15

= 15

= 15 - 9

Add and subtract (left to right)

15 - 9 : 6

15 - 9

15 - 9 = 6

= 6

= 6

= 7 + 4 \cdot 6

Multiply and divide (left to right)

4 \cdot 6 : 24

4 \cdot 6

4 \cdot 6 = 24

= 24

= 7 + 24

Add and subtract (left to right)

7 + 24 : 31

7 + 24

7 + 24 = 31

= 31

= 31

= 4 \cdot 31 - 3 (40 - 8)

Calculate within parentheses

(40 - 8) : 32

40 - 8

40 - 8 = 32

= 32

= 4 \cdot 31 - 3 \cdot 32

Multiply and divide (left to right)

4 \cdot 31 : 124

4 \cdot 31

4 \cdot 31 = 124

= 124

= 124 - 3 \cdot 32

Multiply and divide (left to right)

3 \cdot 32 : 96

3 \cdot 32

3 \cdot 32 = 96

= 96

= 124 - 96

Add and subtract (left to right)

124 - 96 : 28

124 - 96

124 - 96 = 28

= 28

= 28

= 2 \cdot 28

Multiply and divide (left to right)

2 \cdot 28 : 56

2 \cdot 28

2 \cdot 28 = 56

= 56

= 56

2 - (- 4) + 3 + (- 6) - (- 2)

2 (- 3)^{3}

\frac{21.08}{3.4}

5 + (- 3) - 6

\frac{6 ^{2}}{3} (2) + 6

What is 2{4[7+4(5*3-9)]-3(40-8)} ?
The solution to 2{4[7+4(5*3-9)]-3(40-8)} is 56