What is -2+10(-4+3)(2)(-4)(-7)(-3\times 1) ?

The solution to -2+10(-4+3)(2)(-4)(-7)(-3\times 1) is 1678

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-2+10(-4+3)(2)(-4)(-7)(-3\times 1)

- 2 + 10 (- 4 + 3) (2) (- 4) (- 7) (- 3 \cdot 1)

1678

Solution steps

- 2 + 10 (- 4 + 3) (2) (- 4) (- 7) (- 3 \cdot 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 4 + 3) : - 1

- 4 + 3

- 4 + 3 = - 1

= - 1

= - 2 + 10 (- 1) (2) (- 4) (- 7) (- 3 \cdot 1)

Calculate within parentheses

(- 3 \cdot 1) : - 3

- 3 \cdot 1

- 3 \cdot 1 = - 3

= - 3

= - 2 + 10 (- 1) (2) (- 4) (- 7) (- 3)

Multiply and divide (left to right)

10 (- 1) (2) (- 4) (- 7) (- 3) : - 1680

10 (- 1) (2) (- 4) (- 7) (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

10 (- 1) = - 10 \cdot 1 = - 10

= - 10 (2) (- 4) (- 7) (- 3)

10 (2) = 20

10 (2)

Apply rule:

(a) = a

(2) = 2

= 10 \cdot 2

Multiply the numbers:

10 \cdot 2 = 20

= 20

= 20 (- 4) (- 7) (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

20 (- 4) = - 20 \cdot 4 = - 80

= - 80 (- 7) (- 3)

Apply rule

(- a) \cdot (- b) = a \cdot b

(- 80) (- 7) = 80 \cdot 7 = 560

= 560 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

560 (- 3) = - 560 \cdot 3 = - 1680

= - 1680

= - 2 - (- 1680)

Add and subtract (left to right)

- 2 - (- 1680) : 1678

- 2 - (- 1680)

Apply rule

- (- a) = + a

- (- 1680) = + 1680

= - 2 + 1680

- 2 + 1680 = 1678

= 1678

= 1678

3 - 1 - 3 + 5 - 2 + 6

- 3 (2^{2}) + 5 (2^{2}) - 4 (2^{2})

1 - 1 + 3

1 - 1 + 2

24 (6)^{2} + \frac{29}{24} (6) - \frac{62}{3}

What is -2+10(-4+3)(2)(-4)(-7)(-3\times 1) ?
The solution to -2+10(-4+3)(2)(-4)(-7)(-3\times 1) is 1678