The solution to 1-3/4*7/9 is 5/12

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1-3/4*7/9

Solution

1 - \frac{3}{4} \cdot \frac{7}{9}

\frac{5}{12}

Solution steps

1 - \frac{3}{4} \cdot \frac{7}{9}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{3}{4} \cdot \frac{7}{9} : \frac{7}{12}

\frac{3}{4} \cdot \frac{7}{9}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 7}{4 \cdot 9}

Cancel

\frac{3 \cdot 7}{4 \cdot 9} : \frac{7}{12}

\frac{3 \cdot 7}{4 \cdot 9}

Factor the number:

9 = 3 \cdot 3

= \frac{3 \cdot 7}{4 \cdot 3 \cdot 3}

Cancel the common factor:

3

= \frac{7}{4 \cdot 3}

Multiply the numbers:

4 \cdot 3 = 12

= \frac{7}{12}

= \frac{7}{12}

= 1 - \frac{7}{12}

Add and subtract (left to right)

1 - \frac{7}{12} : \frac{5}{12}

1 - \frac{7}{12}

1 - \frac{7}{12} = \frac{5}{12}

1 - \frac{7}{12}

Convert element to fraction:

1 = \frac{1 \cdot 12}{12}

= \frac{1 \cdot 12}{12} - \frac{7}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 12 - 7}{12}

1 \cdot 12 - 7 = 5

1 \cdot 12 - 7

Multiply the numbers:

1 \cdot 12 = 12

= 12 - 7

Subtract the numbers:

12 - 7 = 5

= 5

= \frac{5}{12}

= \frac{5}{12}

= \frac{5}{12}

- 7 + 5 + 4 - (- 9) + 6 - 10

4 \div 5 + 3 \div 3 + 5 \div 6

- 4 (7) + 4

8 \times 2 - 1 \times 9

4 (- 3) + 5